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13131211303 = 739719312447
BaseRepresentation
bin11000011101010111…
…00110001000100111
31020220010200122112101
430032223212020213
5203343042230203
610010555232531
7643255311610
oct141653461047
936803618471
1013131211303
115629254451
122665748747
131313622922
148c7d62c07
1551cc1e41d
hex30eae6227

13131211303 has 16 divisors (see below), whose sum is σ = 15058842624. Its totient is φ = 11216573280.

The previous prime is 13131211279. The next prime is 13131211309. The reversal of 13131211303 is 30311213131.

13131211303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13131211303 - 25 = 13131211271 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13131211309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5365026 + ... + 5367472.

It is an arithmetic number, because the mean of its divisors is an integer number (941177664).

Almost surely, 213131211303 is an apocalyptic number.

13131211303 is a deficient number, since it is larger than the sum of its proper divisors (1927631321).

13131211303 is a wasteful number, since it uses less digits than its factorization.

13131211303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4782.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13131211303 its reverse (30311213131), we get a palindrome (43442424434).

The spelling of 13131211303 in words is "thirteen billion, one hundred thirty-one million, two hundred eleven thousand, three hundred three".

Divisors: 1 7 397 1931 2447 2779 13517 17129 766607 971459 4725157 5366249 6800213 33076099 1875887329 13131211303