Base | Representation |
---|---|
bin | 1011111100010110110011… |
… | …1110011101000111111111 |
3 | 1201111100210211111100002112 |
4 | 2333011230332131013333 |
5 | 3210121400043213143 |
6 | 43532314150444235 |
7 | 2523502612453052 |
oct | 277055476350777 |
9 | 51440724440075 |
10 | 13131543335423 |
11 | 4203068968647 |
12 | 1580b9336367b |
13 | 7433b7515c76 |
14 | 3357da474a99 |
15 | 17b8acc54e18 |
hex | bf16cf9d1ff |
13131543335423 has 8 divisors (see below), whose sum is σ = 13298038900800. Its totient is φ = 12965054607648.
The previous prime is 13131543335419. The next prime is 13131543335501. The reversal of 13131543335423 is 32453334513131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13131543335423 - 22 = 13131543335419 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13131543335023) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2212613 + ... + 5582001.
It is an arithmetic number, because the mean of its divisors is an integer number (1662254862600).
Almost surely, 213131543335423 is an apocalyptic number.
13131543335423 is a deficient number, since it is larger than the sum of its proper divisors (166495565377).
13131543335423 is an equidigital number, since it uses as much as digits as its factorization.
13131543335423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3418801.
The product of its digits is 583200, while the sum is 41.
Adding to 13131543335423 its reverse (32453334513131), we get a palindrome (45584877848554).
The spelling of 13131543335423 in words is "thirteen trillion, one hundred thirty-one billion, five hundred forty-three million, three hundred thirty-five thousand, four hundred twenty-three".
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