1313200031 has 8 divisors (see below), whose sum is σ = 1542780624. Its totient is φ = 1101985920.

The previous prime is 1313200001. The next prime is 1313200033. The reversal of 1313200031 is 1300023131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1313200031 - 2¹⁴ = 1313183647 is a prime.

It is a super-2 number, since 2×1313200031² = 3448988642836801922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1313199979 and 1313200015.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313200033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4591466 + ... + 4591751.

It is an arithmetic number, because the mean of its divisors is an integer number (192847578).

Almost surely, 2^1313200031 is an apocalyptic number.

1313200031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1313200031 is a deficient number, since it is larger than the sum of its proper divisors (229580593).

1313200031 is a wasteful number, since it uses less digits than its factorization.

1313200031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9183241.

The product of its (nonzero) digits is 54, while the sum is 14.

The square root of 1313200031 is about 36238.1019232520. The cubic root of 1313200031 is about 1095.0744042907.

Adding to 1313200031 its reverse (1300023131), we get a palindrome (2613223162).

Subtracting from 1313200031 its reverse (1300023131), we obtain a square (13176900 = 3630²).

The spelling of 1313200031 in words is "one billion, three hundred thirteen million, two hundred thousand, thirty-one".