13132010340031 has 8 divisors (see below), whose sum is σ = 15079820486400. Its totient is φ = 11309865364440.

The previous prime is 13132010339989. The next prime is 13132010340037. The reversal of 13132010340031 is 13004301023131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13132010340031 is a prime.

It is a super-2 number, since 2×13132010340031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13132010339984 and 13132010340011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13132010340037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31416292471 + ... + 31416292888.

It is an arithmetic number, because the mean of its divisors is an integer number (1884977560800).

Almost surely, 2^{13132010340031} is an apocalyptic number.

13132010340031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13132010340031 is a deficient number, since it is larger than the sum of its proper divisors (1947810146369).

13132010340031 is a wasteful number, since it uses less digits than its factorization.

13132010340031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62832585389.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13132010340031 its reverse (13004301023131), we get a palindrome (26136311363162).

The spelling of 13132010340031 in words is "thirteen trillion, one hundred thirty-two billion, ten million, three hundred forty thousand, thirty-one".