1313203321033 has 4 divisors (see below), whose sum is σ = 1331699142528. Its totient is φ = 1294707499540.

The previous prime is 1313203321021. The next prime is 1313203321049. The reversal of 1313203321033 is 3301233023131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313203321033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313203320989 and 1313203321007.

It is not an unprimeable number, because it can be changed into a prime (1313203321433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9247910641 + ... + 9247910782.

It is an arithmetic number, because the mean of its divisors is an integer number (332924785632).

Almost surely, 2^{1313203321033} is an apocalyptic number.

It is an amenable number.

1313203321033 is a deficient number, since it is larger than the sum of its proper divisors (18495821495).

1313203321033 is an equidigital number, since it uses as much as digits as its factorization.

1313203321033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18495821494.

The product of its (nonzero) digits is 2916, while the sum is 25.

Adding to 1313203321033 its reverse (3301233023131), we get a palindrome (4614436344164).

The spelling of 1313203321033 in words is "one trillion, three hundred thirteen billion, two hundred three million, three hundred twenty-one thousand, thirty-three".