Base | Representation |
---|---|
bin | 111101001001101010… |
… | …1111110111101010011 |
3 | 110112221222200122120121 |
4 | 1322103111332331103 |
5 | 4122421141020111 |
6 | 140154505251111 |
7 | 12326154234103 |
oct | 1722325767523 |
9 | 415858618517 |
10 | 131321032531 |
11 | 50769332457 |
12 | 2154b193a97 |
13 | c4ca794ba0 |
14 | 64dab03203 |
15 | 3638d0a871 |
hex | 1e9357ef53 |
131321032531 has 4 divisors (see below), whose sum is σ = 141422650432. Its totient is φ = 121219414632.
The previous prime is 131321032517. The next prime is 131321032541. The reversal of 131321032531 is 135230123131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131321032531 - 213 = 131321024339 is a prime.
It is a super-2 number, since 2×1313210325312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131321032496 and 131321032505.
It is not an unprimeable number, because it can be changed into a prime (131321032541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5050808931 + ... + 5050808956.
It is an arithmetic number, because the mean of its divisors is an integer number (35355662608).
Almost surely, 2131321032531 is an apocalyptic number.
131321032531 is a deficient number, since it is larger than the sum of its proper divisors (10101617901).
131321032531 is a wasteful number, since it uses less digits than its factorization.
131321032531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10101617900.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 131321032531 its reverse (135230123131), we get a palindrome (266551155662).
The spelling of 131321032531 in words is "one hundred thirty-one billion, three hundred twenty-one million, thirty-two thousand, five hundred thirty-one".
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