Base | Representation |
---|---|
bin | 10011000111000001011… |
… | …110100100001100110001 |
3 | 11122112121221020211220201 |
4 | 103013001132210030301 |
5 | 133003424011244221 |
6 | 2443140354035201 |
7 | 163606410445540 |
oct | 23070136441461 |
9 | 4575557224821 |
10 | 1313211040561 |
11 | 466a25440532 |
12 | 192613878b01 |
13 | 96ab211a7c4 |
14 | 477b9d6c157 |
15 | 2425db62891 |
hex | 131c17a4331 |
1313211040561 has 8 divisors (see below), whose sum is σ = 1501246281024. Its totient is φ = 1125284215920.
The previous prime is 1313211040517. The next prime is 1313211040567. The reversal of 1313211040561 is 1650401123131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1313211040561 - 217 = 1313210909489 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1313211040567) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27077995 + ... + 27126448.
It is an arithmetic number, because the mean of its divisors is an integer number (187655785128).
Almost surely, 21313211040561 is an apocalyptic number.
It is an amenable number.
1313211040561 is a deficient number, since it is larger than the sum of its proper divisors (188035240463).
1313211040561 is an equidigital number, since it uses as much as digits as its factorization.
1313211040561 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54207911.
The product of its (nonzero) digits is 2160, while the sum is 28.
Adding to 1313211040561 its reverse (1650401123131), we get a palindrome (2963612163692).
The spelling of 1313211040561 in words is "one trillion, three hundred thirteen billion, two hundred eleven million, forty thousand, five hundred sixty-one".
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