Base | Representation |
---|---|
bin | 11000000001000011100… |
… | …100101001101100111011 |
3 | 12211202222021212211002101 |
4 | 120001003210221230323 |
5 | 204020010141420011 |
6 | 3302103411444231 |
7 | 230144323040005 |
oct | 30010344515473 |
9 | 5752867784071 |
10 | 1650401123131 |
11 | 586a27454262 |
12 | 227a37bb6677 |
13 | bc82ab0b617 |
14 | 59c463d5375 |
15 | 2cde62b02c1 |
hex | 18043929b3b |
1650401123131 has 2 divisors, whose sum is σ = 1650401123132. Its totient is φ = 1650401123130.
The previous prime is 1650401123023. The next prime is 1650401123183. The reversal of 1650401123131 is 1313211040561.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1650401123131 - 27 = 1650401123003 is a prime.
It is a super-2 number, since 2×16504011231312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1650401123131.
It is not a weakly prime, because it can be changed into another prime (1650401123831) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 825200561565 + 825200561566.
It is an arithmetic number, because the mean of its divisors is an integer number (825200561566).
Almost surely, 21650401123131 is an apocalyptic number.
1650401123131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1650401123131 is an equidigital number, since it uses as much as digits as its factorization.
1650401123131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 28.
Adding to 1650401123131 its reverse (1313211040561), we get a palindrome (2963612163692).
The spelling of 1650401123131 in words is "one trillion, six hundred fifty billion, four hundred one million, one hundred twenty-three thousand, one hundred thirty-one".
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