Base | Representation |
---|---|
bin | 1011111100011000111101… |
… | …1110010001110011011001 |
3 | 1201111102022011112202221202 |
4 | 2333012033132101303121 |
5 | 3210124041224244001 |
6 | 43532451423443545 |
7 | 2523523141061066 |
oct | 277061736216331 |
9 | 51442264482852 |
10 | 13132122103001 |
11 | 4203335634260 |
12 | 15811151565b5 |
13 | 74347a3b94a5 |
14 | 335853291c6d |
15 | 17b8e397b96b |
hex | bf18f791cd9 |
13132122103001 has 16 divisors (see below), whose sum is σ = 14390469815040. Its totient is φ = 11884537763280.
The previous prime is 13132122102989. The next prime is 13132122103007. The reversal of 13132122103001 is 10030122123131.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13132122103001 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13132122103007) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25784030 + ... + 26288408.
It is an arithmetic number, because the mean of its divisors is an integer number (899404363440).
Almost surely, 213132122103001 is an apocalyptic number.
13132122103001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13132122103001 is a deficient number, since it is larger than the sum of its proper divisors (1258347712039).
13132122103001 is a wasteful number, since it uses less digits than its factorization.
13132122103001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 515044.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 13132122103001 its reverse (10030122123131), we get a palindrome (23162244226132).
The spelling of 13132122103001 in words is "thirteen trillion, one hundred thirty-two billion, one hundred twenty-two million, one hundred three thousand, one".
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