Base | Representation |
---|---|
bin | 1011111100011001010110… |
… | …0111100111011010011111 |
3 | 1201111102120100120100210202 |
4 | 2333012111213213122133 |
5 | 3210124244123322421 |
6 | 43532505545454115 |
7 | 2523525532361423 |
oct | 277062547473237 |
9 | 51442510510722 |
10 | 13132225214111 |
11 | 4203388860153 |
12 | 15811437a133b |
13 | 74349587c093 |
14 | 335862c52b83 |
15 | 17b8eca4810b |
hex | bf1959e769f |
13132225214111 has 8 divisors (see below), whose sum is σ = 13703234577120. Its totient is φ = 12561219438592.
The previous prime is 13132225214081. The next prime is 13132225214149. The reversal of 13132225214111 is 11141252223131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13132225214111 - 210 = 13132225213087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13132225234111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8826335 + ... + 10206303.
It is an arithmetic number, because the mean of its divisors is an integer number (1712904322140).
Almost surely, 213132225214111 is an apocalyptic number.
13132225214111 is a deficient number, since it is larger than the sum of its proper divisors (571009363009).
13132225214111 is a wasteful number, since it uses less digits than its factorization.
13132225214111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1793745.
The product of its digits is 2880, while the sum is 29.
Adding to 13132225214111 its reverse (11141252223131), we get a palindrome (24273477437242).
The spelling of 13132225214111 in words is "thirteen trillion, one hundred thirty-two billion, two hundred twenty-five million, two hundred fourteen thousand, one hundred eleven".
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