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131322321000000 = 2632561310111113
BaseRepresentation
bin11101110110111111011100…
…010010110101011001000000
3122012222021212100021000200200
4131312333130102311121000
5114203041103134000000
61143144350314045200
736442503351563664
oct3566773422653100
9565867770230620
10131322321000000
1138930535703059
121288b18b719800
135837845b72a20
142460069da68a4
15102aedcda8500
hex776fdc4b5640

131322321000000 has 1176 divisors, whose sum is σ = 511764496049352. Its totient is φ = 32002560000000.

The previous prime is 131322320999999. The next prime is 131322321000001. The reversal of 131322321000000 is 123223131.

131322321000000 is a `hidden beast` number, since 131 + 322 + 3 + 210 + 0 + 0 + 0 + 0 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (131322320999999) and next prime (131322321000001).

It can be written as a sum of positive squares in 28 ways, for example, as 29193187037184 + 102129133962816 = 5403072^2 + 10105896^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (131322321000001) by changing a digit.

It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 11816994444 + ... + 11817005556.

Almost surely, 2131322321000000 is an apocalyptic number.

131322321000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131322321000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (255882248024676).

131322321000000 is an abundant number, since it is smaller than the sum of its proper divisors (380442175049352).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131322321000000 is a wasteful number, since it uses less digits than its factorization.

131322321000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11275 (or 11237 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 131322321000000 its reverse (123223131), we get a palindrome (131322444223131).

The spelling of 131322321000000 in words is "one hundred thirty-one trillion, three hundred twenty-two billion, three hundred twenty-one million", and thus it is an aban number.