Base | Representation |
---|---|
bin | 1011111100011001011011… |
… | …0000111110010010010111 |
3 | 1201111102121200202100200101 |
4 | 2333012112300332102113 |
5 | 3210124314034204221 |
6 | 43532511513554531 |
7 | 2523526155003226 |
oct | 277062660762227 |
9 | 51442550670611 |
10 | 13132244444311 |
11 | 42033986a5083 |
12 | 158114a115a47 |
13 | 743499852cb5 |
14 | 33586561acbd |
15 | 17b8ee595d91 |
hex | bf196c3e497 |
13132244444311 has 4 divisors (see below), whose sum is σ = 13132310172592. Its totient is φ = 13132178716032.
The previous prime is 13132244444279. The next prime is 13132244444317. The reversal of 13132244444311 is 11344444223131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13132244444311 - 25 = 13132244444279 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13132244444317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32563530 + ... + 32964343.
It is an arithmetic number, because the mean of its divisors is an integer number (3283077543148).
Almost surely, 213132244444311 is an apocalyptic number.
13132244444311 is a deficient number, since it is larger than the sum of its proper divisors (65728281).
13132244444311 is an equidigital number, since it uses as much as digits as its factorization.
13132244444311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65728280.
The product of its digits is 110592, while the sum is 37.
Adding to 13132244444311 its reverse (11344444223131), we get a palindrome (24476688667442).
The spelling of 13132244444311 in words is "thirteen trillion, one hundred thirty-two billion, two hundred forty-four million, four hundred forty-four thousand, three hundred eleven".
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