Base | Representation |
---|---|
bin | 1011111100011001101011… |
… | …1011000111001011011010 |
3 | 1201111102210120000212122002 |
4 | 2333012122323013023122 |
5 | 3210124434414223114 |
6 | 43532522445201002 |
7 | 2523530663005604 |
oct | 277063273071332 |
9 | 51442716025562 |
10 | 13132314211034 |
11 | 4203424016927 |
12 | 1581169560162 |
13 | 7434ab13c595 |
14 | 3358709bc174 |
15 | 17b9057777de |
hex | bf19aec72da |
13132314211034 has 8 divisors (see below), whose sum is σ = 19710805993428. Its totient is φ = 6562045546560.
The previous prime is 13132314211031. The next prime is 13132314211073. The reversal of 13132314211034 is 43011241323131.
It can be written as a sum of positive squares in 2 ways, for example, as 13123194534025 + 9119677009 = 3622595^2 + 95497^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13132314210988 and 13132314211006.
It is not an unprimeable number, because it can be changed into a prime (13132314211031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2055775487 + ... + 2055781874.
Almost surely, 213132314211034 is an apocalyptic number.
13132314211034 is a deficient number, since it is larger than the sum of its proper divisors (6578491782394).
13132314211034 is a wasteful number, since it uses less digits than its factorization.
13132314211034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4111558960.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 13132314211034 its reverse (43011241323131), we get a palindrome (56143555534165).
The spelling of 13132314211034 in words is "thirteen trillion, one hundred thirty-two billion, three hundred fourteen million, two hundred eleven thousand, thirty-four".
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