Base | Representation |
---|---|
bin | 111101001001101111… |
… | …0010011001010011010 |
3 | 110112222010210101212001 |
4 | 1322103132103022122 |
5 | 4122422220244232 |
6 | 140155024111214 |
7 | 12326211613402 |
oct | 1722336231232 |
9 | 415863711761 |
10 | 131323212442 |
11 | 5076a591234 |
12 | 2154ba6550a |
13 | c4cb079186 |
14 | 64db10d802 |
15 | 36390db6e7 |
hex | 1e9379329a |
131323212442 has 4 divisors (see below), whose sum is σ = 196984818666. Its totient is φ = 65661606220.
The previous prime is 131323212409. The next prime is 131323212443. The reversal of 131323212442 is 244212323131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 76352189761 + 54971022681 = 276319^2 + 234459^2 .
It is a super-2 number, since 2×1313232124422 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131323212442.
It is not an unprimeable number, because it can be changed into a prime (131323212443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32830803109 + ... + 32830803112.
Almost surely, 2131323212442 is an apocalyptic number.
131323212442 is a deficient number, since it is larger than the sum of its proper divisors (65661606224).
131323212442 is an equidigital number, since it uses as much as digits as its factorization.
131323212442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65661606223.
The product of its digits is 6912, while the sum is 28.
Adding to 131323212442 its reverse (244212323131), we get a palindrome (375535535573).
The spelling of 131323212442 in words is "one hundred thirty-one billion, three hundred twenty-three million, two hundred twelve thousand, four hundred forty-two".
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