13132330401009 has 4 divisors (see below), whose sum is σ = 17509773868016. Its totient is φ = 8754886934004.

The previous prime is 13132330400971. The next prime is 13132330401017. The reversal of 13132330401009 is 90010403323131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13132330401009 - 2¹³ = 13132330392817 is a prime.

It is a super-3 number, since 3×13132330401009³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13132330401059) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188721733499 + ... + 2188721733504.

It is an arithmetic number, because the mean of its divisors is an integer number (4377443467004).

Almost surely, 2^{13132330401009} is an apocalyptic number.

It is an amenable number.

13132330401009 is a deficient number, since it is larger than the sum of its proper divisors (4377443467007).

13132330401009 is an equidigital number, since it uses as much as digits as its factorization.

13132330401009 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4377443467006.

The product of its (nonzero) digits is 5832, while the sum is 30.

The spelling of 13132330401009 in words is "thirteen trillion, one hundred thirty-two billion, three hundred thirty million, four hundred one thousand, nine".