Base | Representation |
---|---|
bin | 11000011101100000… |
… | …01000011100110001 |
3 | 1020220012221001201020 |
4 | 30032300020130301 |
5 | 203343343303213 |
6 | 10011040530053 |
7 | 643301363505 |
oct | 141660103461 |
9 | 36805831636 |
10 | 13132400433 |
11 | 56299968a9 |
12 | 2666020929 |
13 | 131394ac59 |
14 | 8c8192305 |
15 | 51cda6923 |
hex | 30ec08731 |
13132400433 has 8 divisors (see below), whose sum is σ = 17796914496. Its totient is φ = 8611410000.
The previous prime is 13132400419. The next prime is 13132400447. The reversal of 13132400433 is 33400423131.
It is an interprime number because it is at equal distance from previous prime (13132400419) and next prime (13132400447).
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13132400433 - 210 = 13132399409 is a prime.
It is a super-2 number, since 2×131324004332 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13132400233) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35880693 + ... + 35881058.
It is an arithmetic number, because the mean of its divisors is an integer number (2224614312).
Almost surely, 213132400433 is an apocalyptic number.
It is an amenable number.
13132400433 is a deficient number, since it is larger than the sum of its proper divisors (4664514063).
13132400433 is an equidigital number, since it uses as much as digits as its factorization.
13132400433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 71761815.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 13132400433 its reverse (33400423131), we get a palindrome (46532823564).
The spelling of 13132400433 in words is "thirteen billion, one hundred thirty-two million, four hundred thousand, four hundred thirty-three".
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