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1313240200131 = 33161231489547
BaseRepresentation
bin10011000111000011001…
…101110011001111000011
311122112200222010022022210
4103013003031303033003
5133004003442401011
62443143315033203
7163610213344056
oct23070315631703
94575628108283
101313240200131
11466a3a947552
1219262159b803
1396ab818a0a2
14477bdb9ca9d
15242614c26a6
hex131c33733c3

1313240200131 has 16 divisors (see below), whose sum is σ = 1837101052928. Its totient is φ = 833362365600.

The previous prime is 1313240200109. The next prime is 1313240200141. The reversal of 1313240200131 is 1310020423131.

It is not a de Polignac number, because 1313240200131 - 27 = 1313240200003 is a prime.

It is a super-2 number, since 2×13132402001312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1313240200098 and 1313240200107.

It is not an unprimeable number, because it can be changed into a prime (1313240200141) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 115739101 + ... + 115750446.

It is an arithmetic number, because the mean of its divisors is an integer number (114818815808).

Almost surely, 21313240200131 is an apocalyptic number.

1313240200131 is a deficient number, since it is larger than the sum of its proper divisors (523860852797).

1313240200131 is a wasteful number, since it uses less digits than its factorization.

1313240200131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 231489642.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1313240200131 its reverse (1310020423131), we get a palindrome (2623260623262).

The spelling of 1313240200131 in words is "one trillion, three hundred thirteen billion, two hundred forty million, two hundred thousand, one hundred thirty-one".

Divisors: 1 3 31 61 93 183 1891 5673 231489547 694468641 7176175957 14120862367 21528527871 42362587101 437746733377 1313240200131