Base | Representation |
---|---|
bin | 10011000111000011001… |
… | …101110011001101000011 |
3 | 11122112200222010022011001 |
4 | 103013003031303031003 |
5 | 133004003442400003 |
6 | 2443143315032431 |
7 | 163610213343514 |
oct | 23070315631503 |
9 | 4575628108131 |
10 | 1313240200003 |
11 | 466a3a947446 |
12 | 19262159b717 |
13 | 96ab818a004 |
14 | 477bdb9ca0b |
15 | 242614c261d |
hex | 131c3373343 |
1313240200003 has 2 divisors, whose sum is σ = 1313240200004. Its totient is φ = 1313240200002.
The previous prime is 1313240199941. The next prime is 1313240200031. The reversal of 1313240200003 is 3000020423131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313240200003 - 225 = 1313206645571 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313240200403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656620100001 + 656620100002.
It is an arithmetic number, because the mean of its divisors is an integer number (656620100002).
Almost surely, 21313240200003 is an apocalyptic number.
1313240200003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313240200003 is an equidigital number, since it uses as much as digits as its factorization.
1313240200003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 1313240200003 its reverse (3000020423131), we get a palindrome (4313260623134).
The spelling of 1313240200003 in words is "one trillion, three hundred thirteen billion, two hundred forty million, two hundred thousand, three".
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