Base | Representation |
---|---|
bin | 10011000111000011011… |
… | …010000001001011111001 |
3 | 11122112201012011000211121 |
4 | 103013003122001023321 |
5 | 133004010302344001 |
6 | 2443143511425241 |
7 | 163610252513635 |
oct | 23070332011371 |
9 | 4575635130747 |
10 | 1313243403001 |
11 | 466a41734952 |
12 | 192622685221 |
13 | 96ab8a3bb8a |
14 | 477c0393dc5 |
15 | 242619066a1 |
hex | 131c36812f9 |
1313243403001 has 8 divisors (see below), whose sum is σ = 1320265257984. Its totient is φ = 1306223071680.
The previous prime is 1313243402981. The next prime is 1313243403037. The reversal of 1313243403001 is 1003043423131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1313243403001 - 25 = 1313243402969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1313243403041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1368916 + ... + 2121418.
It is an arithmetic number, because the mean of its divisors is an integer number (165033157248).
Almost surely, 21313243403001 is an apocalyptic number.
It is an amenable number.
1313243403001 is a deficient number, since it is larger than the sum of its proper divisors (7021854983).
1313243403001 is an equidigital number, since it uses as much as digits as its factorization.
1313243403001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 761831.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1313243403001 its reverse (1003043423131), we get a palindrome (2316286826132).
The spelling of 1313243403001 in words is "one trillion, three hundred thirteen billion, two hundred forty-three million, four hundred three thousand, one".
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