Base | Representation |
---|---|
bin | 111101001001110010… |
… | …1001011100111110010 |
3 | 110112222021012001122022 |
4 | 1322103211023213302 |
5 | 4122423201012222 |
6 | 140155130511442 |
7 | 12326233136255 |
oct | 1722345134762 |
9 | 415867161568 |
10 | 131325016562 |
11 | 50770603743 |
12 | 21550595582 |
13 | c4cb55b3bc |
14 | 64db45d09c |
15 | 3639346042 |
hex | 1e9394b9f2 |
131325016562 has 4 divisors (see below), whose sum is σ = 196987524846. Its totient is φ = 65662508280.
The previous prime is 131325016523. The next prime is 131325016577. The reversal of 131325016562 is 265610523131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 84157429801 + 47167586761 = 290099^2 + 217181^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32831254139 + ... + 32831254142.
Almost surely, 2131325016562 is an apocalyptic number.
131325016562 is a deficient number, since it is larger than the sum of its proper divisors (65662508284).
131325016562 is an equidigital number, since it uses as much as digits as its factorization.
131325016562 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65662508283.
The product of its (nonzero) digits is 32400, while the sum is 35.
Adding to 131325016562 its reverse (265610523131), we get a palindrome (396935539693).
The spelling of 131325016562 in words is "one hundred thirty-one billion, three hundred twenty-five million, sixteen thousand, five hundred sixty-two".
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