Base | Representation |
---|---|
bin | 10011000111000011110… |
… | …111011101010000000011 |
3 | 11122112201201200002202020 |
4 | 103013003313131100003 |
5 | 133004014241321011 |
6 | 2443144345052523 |
7 | 163610405224566 |
oct | 23070367352003 |
9 | 4575651602666 |
10 | 1313251120131 |
11 | 466a46025945 |
12 | 192625187143 |
13 | 96aba511622 |
14 | 477c14024dd |
15 | 2426242d006 |
hex | 131c3ddd403 |
1313251120131 has 16 divisors (see below), whose sum is σ = 1754053297920. Its totient is φ = 873975445280.
The previous prime is 1313251120109. The next prime is 1313251120169. The reversal of 1313251120131 is 1310211523131.
It is a cyclic number.
It is not a de Polignac number, because 1313251120131 - 222 = 1313246925827 is a prime.
It is a super-2 number, since 2×13132511201312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1313251120031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8988121 + ... + 9133061.
It is an arithmetic number, because the mean of its divisors is an integer number (109628331120).
Almost surely, 21313251120131 is an apocalyptic number.
1313251120131 is a deficient number, since it is larger than the sum of its proper divisors (440802177789).
1313251120131 is a wasteful number, since it uses less digits than its factorization.
1313251120131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150186.
The product of its (nonzero) digits is 540, while the sum is 24.
Adding to 1313251120131 its reverse (1310211523131), we get a palindrome (2623462643262).
The spelling of 1313251120131 in words is "one trillion, three hundred thirteen billion, two hundred fifty-one million, one hundred twenty thousand, one hundred thirty-one".
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