Base | Representation |
---|---|
bin | 11000011101100001… |
… | …01101111110010111 |
3 | 1020220020012212112220 |
4 | 30032300231332113 |
5 | 203343413213020 |
6 | 10011044113423 |
7 | 643302603561 |
oct | 141660557627 |
9 | 36806185486 |
10 | 13132554135 |
11 | 5629a91328 |
12 | 2666095873 |
13 | 13139a2bbc |
14 | 8c81d2331 |
15 | 51cdd7240 |
hex | 30ec2df97 |
13132554135 has 8 divisors (see below), whose sum is σ = 21012086640. Its totient is φ = 7004028864.
The previous prime is 13132554131. The next prime is 13132554137. The reversal of 13132554135 is 53145523131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13132554135 - 22 = 13132554131 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13132554096 and 13132554105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13132554131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 437751790 + ... + 437751819.
It is an arithmetic number, because the mean of its divisors is an integer number (2626510830).
Almost surely, 213132554135 is an apocalyptic number.
13132554135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13132554135 is a deficient number, since it is larger than the sum of its proper divisors (7879532505).
13132554135 is an equidigital number, since it uses as much as digits as its factorization.
13132554135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 875503617.
The product of its digits is 27000, while the sum is 33.
The spelling of 13132554135 in words is "thirteen billion, one hundred thirty-two million, five hundred fifty-four thousand, one hundred thirty-five".
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