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13133020034 = 26566510017
BaseRepresentation
bin11000011101100100…
…11111101110000010
31020220021002112122102
430032302133232002
5203344023120114
610011102110402
7643306554101
oct141662375602
936807075572
1013133020034
11562a27a372
12266627b402
131313b06c94
148c82b4038
1551ce7a2de
hex30ec9fb82

13133020034 has 4 divisors (see below), whose sum is σ = 19699530054. Its totient is φ = 6566510016.

The previous prime is 13133020009. The next prime is 13133020049. The reversal of 13133020034 is 43002033131.

13133020034 is digitally balanced in base 5, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13132014025 + 1006009 = 114595^2 + 1003^2 .

It is a super-2 number, since 2×131330200342 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13133019988 and 13133020015.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283255007 + ... + 3283255010.

Almost surely, 213133020034 is an apocalyptic number.

13133020034 is a deficient number, since it is larger than the sum of its proper divisors (6566510020).

13133020034 is an equidigital number, since it uses as much as digits as its factorization.

13133020034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6566510019.

The product of its (nonzero) digits is 648, while the sum is 20.

Adding to 13133020034 its reverse (43002033131), we get a palindrome (56135053165).

The spelling of 13133020034 in words is "thirteen billion, one hundred thirty-three million, twenty thousand, thirty-four".

Divisors: 1 2 6566510017 13133020034