Base | Representation |
---|---|
bin | 111101001001111100… |
… | …1000100111100111001 |
3 | 110112222122000001001011 |
4 | 1322103321010330321 |
5 | 4122431014411441 |
6 | 140155434353521 |
7 | 12326325361054 |
oct | 1722371047471 |
9 | 415878001034 |
10 | 131330232121 |
11 | 50773546220 |
12 | 2155228b8a1 |
13 | c4cc66632a |
14 | 64dc019a9b |
15 | 3639a26581 |
hex | 1e93e44f39 |
131330232121 has 32 divisors (see below), whose sum is σ = 148500011520. Its totient is φ = 115095168000.
The previous prime is 131330232119. The next prime is 131330232149. The reversal of 131330232121 is 121232033131.
It is a cyclic number.
It is not a de Polignac number, because 131330232121 - 21 = 131330232119 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131330232092 and 131330232101.
It is not an unprimeable number, because it can be changed into a prime (131330232521) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 33509200 + ... + 33513118.
It is an arithmetic number, because the mean of its divisors is an integer number (4640625360).
Almost surely, 2131330232121 is an apocalyptic number.
131330232121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131330232121 is a deficient number, since it is larger than the sum of its proper divisors (17169779399).
131330232121 is a wasteful number, since it uses less digits than its factorization.
131330232121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4705.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 131330232121 its reverse (121232033131), we get a palindrome (252562265252).
The spelling of 131330232121 in words is "one hundred thirty-one billion, three hundred thirty million, two hundred thirty-two thousand, one hundred twenty-one".
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