Base | Representation |
---|---|
bin | 10011000111000110111… |
… | …110001101011101100001 |
3 | 11122112212100201011020021 |
4 | 103013012332031131201 |
5 | 133004121111101423 |
6 | 2443153445513441 |
7 | 163611610125451 |
oct | 23070676153541 |
9 | 4575770634207 |
10 | 1313303222113 |
11 | 466a72481933 |
12 | 19263a712881 |
13 | 96ac82546bc |
14 | 477c82c5d61 |
15 | 24266cc095d |
hex | 131c6f8d761 |
1313303222113 has 4 divisors (see below), whose sum is σ = 1313306222740. Its totient is φ = 1313300221488.
The previous prime is 1313303222069. The next prime is 1313303222117. The reversal of 1313303222113 is 3112223033131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1071531381904 + 241771840209 = 1035148^2 + 491703^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313303222113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1313303222117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 702318 + ... + 1766311.
It is an arithmetic number, because the mean of its divisors is an integer number (328326555685).
Almost surely, 21313303222113 is an apocalyptic number.
It is an amenable number.
1313303222113 is a deficient number, since it is larger than the sum of its proper divisors (3000627).
1313303222113 is an equidigital number, since it uses as much as digits as its factorization.
1313303222113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3000626.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1313303222113 its reverse (3112223033131), we get a palindrome (4425526255244).
The spelling of 1313303222113 in words is "one trillion, three hundred thirteen billion, three hundred three million, two hundred twenty-two thousand, one hundred thirteen".
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