131330455520045 has 4 divisors (see below), whose sum is σ = 157596546624060. Its totient is φ = 105064364416032.

The previous prime is 131330455520041. The next prime is 131330455520053. The reversal of 131330455520045 is 540025554033131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 27457117922116 + 103873337597929 = 5239954^2 + 10191827^2 .

It is a cyclic number.

It is not a de Polignac number, because 131330455520045 - 2² = 131330455520041 is a prime.

It is a super-2 number, since 2×131330455520045² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131330455519984 and 131330455520011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131330455520041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13133045552000 + ... + 13133045552009.

It is an arithmetic number, because the mean of its divisors is an integer number (39399136656015).

Almost surely, 2^{131330455520045} is an apocalyptic number.

It is an amenable number.

131330455520045 is a deficient number, since it is larger than the sum of its proper divisors (26266091104015).

131330455520045 is an equidigital number, since it uses as much as digits as its factorization.

131330455520045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26266091104014.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 131330455520045 in words is "one hundred thirty-one trillion, three hundred thirty billion, four hundred fifty-five million, five hundred twenty thousand, forty-five".