13133100301 has 4 divisors (see below), whose sum is σ = 13134272704. Its totient is φ = 13131927900.

The previous prime is 13133100269. The next prime is 13133100311. The reversal of 13133100301 is 10300133131.

13133100301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13133100301 - 2⁵ = 13133100269 is a prime.

It is a super-2 number, since 2×13133100301² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13133100311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 569235 + ... + 591856.

It is an arithmetic number, because the mean of its divisors is an integer number (3283568176).

Almost surely, 2^13133100301 is an apocalyptic number.

It is an amenable number.

13133100301 is a deficient number, since it is larger than the sum of its proper divisors (1172403).

13133100301 is a wasteful number, since it uses less digits than its factorization.

13133100301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1172402.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 13133100301 its reverse (10300133131), we get a palindrome (23433233432).

The spelling of 13133100301 in words is "thirteen billion, one hundred thirty-three million, one hundred thousand, three hundred one".