131331004033 has 4 divisors (see below), whose sum is σ = 138243162160. Its totient is φ = 124418845908.

The previous prime is 131331003971. The next prime is 131331004097. The reversal of 131331004033 is 330400133131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131331004033 - 2⁹ = 131331003521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131331003995 and 131331004013.

It is not an unprimeable number, because it can be changed into a prime (131331004333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3456079035 + ... + 3456079072.

It is an arithmetic number, because the mean of its divisors is an integer number (34560790540).

Almost surely, 2^131331004033 is an apocalyptic number.

It is an amenable number.

131331004033 is a deficient number, since it is larger than the sum of its proper divisors (6912158127).

131331004033 is an equidigital number, since it uses as much as digits as its factorization.

131331004033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6912158126.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 131331004033 its reverse (330400133131), we get a palindrome (461731137164).

The spelling of 131331004033 in words is "one hundred thirty-one billion, three hundred thirty-one million, four thousand, thirty-three".