Base | Representation |
---|---|
bin | 11000011101100101… |
… | …10110100000111011 |
3 | 1020220021021021201112 |
4 | 30032302312200323 |
5 | 203344034112103 |
6 | 10011104110535 |
7 | 643310423234 |
oct | 141662664073 |
9 | 36807237645 |
10 | 13133113403 |
11 | 562a333533 |
12 | 266630544b |
13 | 1313b3a627 |
14 | 8c82da08b |
15 | 51ce97cd8 |
hex | 30ecb683b |
13133113403 has 4 divisors (see below), whose sum is σ = 13139594520. Its totient is φ = 13126632288.
The previous prime is 13133113393. The next prime is 13133113417. The reversal of 13133113403 is 30431133131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30431133131 = 7 ⋅4347304733.
It is a cyclic number.
It is not a de Polignac number, because 13133113403 - 24 = 13133113387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13133113423) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3237518 + ... + 3241571.
It is an arithmetic number, because the mean of its divisors is an integer number (3284898630).
Almost surely, 213133113403 is an apocalyptic number.
13133113403 is a deficient number, since it is larger than the sum of its proper divisors (6481117).
13133113403 is an equidigital number, since it uses as much as digits as its factorization.
13133113403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6481116.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 13133113403 its reverse (30431133131), we get a palindrome (43564246534).
The spelling of 13133113403 in words is "thirteen billion, one hundred thirty-three million, one hundred thirteen thousand, four hundred three".
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