Base | Representation |
---|---|
bin | 1011111100011101011001… |
… | …0010111100001000101011 |
3 | 1201111112100222101002122121 |
4 | 2333013112102330020223 |
5 | 3210134004420004003 |
6 | 43533205351132111 |
7 | 2523564446513146 |
oct | 277072622741053 |
9 | 51445328332577 |
10 | 13133310313003 |
11 | 4203895317aa1 |
12 | 15813a7074037 |
13 | 74360961342a |
14 | 335926dd305d |
15 | 17b962e38cbd |
hex | bf1d64bc22b |
13133310313003 has 4 divisors (see below), whose sum is σ = 13133331024280. Its totient is φ = 13133289601728.
The previous prime is 13133310312953. The next prime is 13133310313031. The reversal of 13133310313003 is 30031301333131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13133310313003 - 29 = 13133310312491 is a prime.
It is a super-3 number, since 3×131333103130033 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13133310313073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9373413 + ... + 10683046.
It is an arithmetic number, because the mean of its divisors is an integer number (3283332756070).
Almost surely, 213133310313003 is an apocalyptic number.
13133310313003 is a deficient number, since it is larger than the sum of its proper divisors (20711277).
13133310313003 is an equidigital number, since it uses as much as digits as its factorization.
13133310313003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20711276.
The product of its (nonzero) digits is 2187, while the sum is 25.
Adding to 13133310313003 its reverse (30031301333131), we get a palindrome (43164611646134).
The spelling of 13133310313003 in words is "thirteen trillion, one hundred thirty-three billion, three hundred ten million, three hundred thirteen thousand, three".
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