Base | Representation |
---|---|
bin | 11000011101100111… |
… | …01010000010101001 |
3 | 1020220021200000020100 |
4 | 30032303222002221 |
5 | 203344112340312 |
6 | 10011112420013 |
7 | 643312262451 |
oct | 141663520251 |
9 | 36807600210 |
10 | 13133324457 |
11 | 562a468060 |
12 | 26663a7609 |
13 | 1313bb2706 |
14 | 8c8352d61 |
15 | 51ceda5dc |
hex | 30ecea0a9 |
13133324457 has 48 divisors (see below), whose sum is σ = 21802173120. Its totient is φ = 7534425600.
The previous prime is 13133324443. The next prime is 13133324521. The reversal of 13133324457 is 75442333131.
13133324457 is a `hidden beast` number, since 1 + 31 + 333 + 244 + 57 = 666.
It is not a de Polignac number, because 13133324457 - 24 = 13133324441 is a prime.
It is a super-3 number, since 3×131333244573 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (13135324457) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 3235173 + ... + 3239229.
It is an arithmetic number, because the mean of its divisors is an integer number (454211940).
Almost surely, 213133324457 is an apocalyptic number.
It is an amenable number.
13133324457 is a deficient number, since it is larger than the sum of its proper divisors (8668848663).
13133324457 is a wasteful number, since it uses less digits than its factorization.
13133324457 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5814 (or 5811 counting only the distinct ones).
The product of its digits is 90720, while the sum is 36.
Adding to 13133324457 its reverse (75442333131), we get a palindrome (88575657588).
The spelling of 13133324457 in words is "thirteen billion, one hundred thirty-three million, three hundred twenty-four thousand, four hundred fifty-seven".
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