Base | Representation |
---|---|
bin | 11101110111001001110011… |
… | …001011111111111011001001 |
3 | 122020000100120102022212210221 |
4 | 131313021303023333323021 |
5 | 114203231342240033340 |
6 | 1143153430042310041 |
7 | 36443346065026036 |
oct | 3567116313777311 |
9 | 566010512285727 |
10 | 131333442502345 |
11 | 38935222489406 |
12 | 128913741b8321 |
13 | 58388c8ccc045 |
14 | 246080306438d |
15 | 102b43e44844a |
hex | 7772732ffec9 |
131333442502345 has 32 divisors (see below), whose sum is σ = 174129974519040. Its totient is φ = 94584777830400.
The previous prime is 131333442502309. The next prime is 131333442502373. The reversal of 131333442502345 is 543205244333131.
It is not a de Polignac number, because 131333442502345 - 215 = 131333442469577 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 86934801 + ... + 88432609.
It is an arithmetic number, because the mean of its divisors is an integer number (5441561703720).
Almost surely, 2131333442502345 is an apocalyptic number.
It is an amenable number.
131333442502345 is a deficient number, since it is larger than the sum of its proper divisors (42796532016695).
131333442502345 is a wasteful number, since it uses less digits than its factorization.
131333442502345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1542705.
The product of its (nonzero) digits is 1555200, while the sum is 43.
Adding to 131333442502345 its reverse (543205244333131), we get a palindrome (674538686835476).
The spelling of 131333442502345 in words is "one hundred thirty-one trillion, three hundred thirty-three billion, four hundred forty-two million, five hundred two thousand, three hundred forty-five".
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