Base | Representation |
---|---|
bin | 11101110111001010011010… |
… | …011101100111101011011111 |
3 | 122020000102021100020000211001 |
4 | 131313022122131213223133 |
5 | 114203234214431324210 |
6 | 1143154015301411131 |
7 | 36443401315606603 |
oct | 3567123235475337 |
9 | 566012240200731 |
10 | 131334101433055 |
11 | 38935530427844 |
12 | 12891518a09aa7 |
13 | 58389a268bc81 |
14 | 246086678b503 |
15 | 102b47c20703a |
hex | 77729a767adf |
131334101433055 has 16 divisors (see below), whose sum is σ = 166879114237440. Its totient is φ = 98882378732032.
The previous prime is 131334101433053. The next prime is 131334101433167. The reversal of 131334101433055 is 550334101433131.
It is a cyclic number.
It is not a de Polignac number, because 131334101433055 - 21 = 131334101433053 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131334101433053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33063679 + ... + 36822208.
It is an arithmetic number, because the mean of its divisors is an integer number (10429944639840).
Almost surely, 2131334101433055 is an apocalyptic number.
131334101433055 is a deficient number, since it is larger than the sum of its proper divisors (35545012804385).
131334101433055 is a wasteful number, since it uses less digits than its factorization.
131334101433055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69908018.
The product of its (nonzero) digits is 97200, while the sum is 37.
Adding to 131334101433055 its reverse (550334101433131), we get a palindrome (681668202866186).
The spelling of 131334101433055 in words is "one hundred thirty-one trillion, three hundred thirty-four billion, one hundred one million, four hundred thirty-three thousand, fifty-five".
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