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131340035 = 5109124077
BaseRepresentation
bin1111101010000…
…01011100000011
3100011010202122202
413311001130003
5232110340120
621011023415
73153241361
oct765013403
9304122582
10131340035
1168157792
1237b9ab6b
13212976c8
141362c631
15b7e5875
hex7d41703

131340035 has 8 divisors (see below), whose sum is σ = 157759056. Its totient is φ = 104971360.

The previous prime is 131340023. The next prime is 131340049. The reversal of 131340035 is 530043131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131340035 - 28 = 131339779 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131339989 and 131340016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6584 + ... + 17493.

It is an arithmetic number, because the mean of its divisors is an integer number (19719882).

Almost surely, 2131340035 is an apocalyptic number.

131340035 is a deficient number, since it is larger than the sum of its proper divisors (26419021).

131340035 is a wasteful number, since it uses less digits than its factorization.

131340035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 25173.

The product of its (nonzero) digits is 540, while the sum is 20.

The square root of 131340035 is about 11460.3680132882. The cubic root of 131340035 is about 508.3143566029.

Adding to 131340035 its reverse (530043131), we get a palindrome (661383166).

The spelling of 131340035 in words is "one hundred thirty-one million, three hundred forty thousand, thirty-five".

Divisors: 1 5 1091 5455 24077 120385 26268007 131340035