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13134040433 = 83158241451
BaseRepresentation
bin11000011101101100…
…11000110101110001
31020220100000101100222
430032312120311301
5203344303243213
610011140022425
7643321334033
oct141666306561
936810011328
1013134040433
11562a906a78
122666691a15
1313140a3577
148c849bc53
1551d0cc808
hex30ed98d71

13134040433 has 4 divisors (see below), whose sum is σ = 13292281968. Its totient is φ = 12975798900.

The previous prime is 13134040429. The next prime is 13134040487. The reversal of 13134040433 is 33404043131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13134040433 - 22 = 13134040429 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13134040133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79120643 + ... + 79120808.

It is an arithmetic number, because the mean of its divisors is an integer number (3323070492).

Almost surely, 213134040433 is an apocalyptic number.

It is an amenable number.

13134040433 is a deficient number, since it is larger than the sum of its proper divisors (158241535).

13134040433 is an equidigital number, since it uses as much as digits as its factorization.

13134040433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 158241534.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 13134040433 its reverse (33404043131), we get a palindrome (46538083564).

The spelling of 13134040433 in words is "thirteen billion, one hundred thirty-four million, forty thousand, four hundred thirty-three".

Divisors: 1 83 158241451 13134040433