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13134104402 = 231720716253
BaseRepresentation
bin11000011101101101…
…01000011101010010
31020220100010122010012
430032312220131102
5203344312320102
610011141234522
7643322021366
oct141666503522
936810118105
1013134104402
11562a950041
122666702a42
1313140c6713
148c84b72a6
1551d0e1752
hex30eda8752

13134104402 has 8 divisors (see below), whose sum is σ = 19763306316. Its totient is φ = 6546335632.

The previous prime is 13134104387. The next prime is 13134104419. The reversal of 13134104402 is 20440143131.

13134104402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 12887017441 + 247086961 = 113521^2 + 15719^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×131341044023 (a number of 31 digits) contains 333 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10357493 + ... + 10358760.

Almost surely, 213134104402 is an apocalyptic number.

13134104402 is a deficient number, since it is larger than the sum of its proper divisors (6629201914).

13134104402 is a wasteful number, since it uses less digits than its factorization.

13134104402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20716572.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13134104402 its reverse (20440143131), we get a palindrome (33574247533).

The spelling of 13134104402 in words is "thirteen billion, one hundred thirty-four million, one hundred four thousand, four hundred two".

Divisors: 1 2 317 634 20716253 41432506 6567052201 13134104402