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13134110413 = 18796989947
BaseRepresentation
bin11000011101101101…
…01001111011001101
31020220100010221100211
430032312221323031
5203344313013123
610011141322421
7643322045044
oct141666517315
936810127324
1013134110413
11562a954606
122666706411
1313140c9388
148c84b955b
1551d0e340d
hex30eda9ecd

13134110413 has 4 divisors (see below), whose sum is σ = 13141102240. Its totient is φ = 13127118588.

The previous prime is 13134110389. The next prime is 13134110471. The reversal of 13134110413 is 31401143131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13134110413 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13134110513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3493095 + ... + 3496852.

It is an arithmetic number, because the mean of its divisors is an integer number (3285275560).

Almost surely, 213134110413 is an apocalyptic number.

It is an amenable number.

13134110413 is a deficient number, since it is larger than the sum of its proper divisors (6991827).

13134110413 is an equidigital number, since it uses as much as digits as its factorization.

13134110413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6991826.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13134110413 its reverse (31401143131), we get a palindrome (44535253544).

The spelling of 13134110413 in words is "thirteen billion, one hundred thirty-four million, one hundred ten thousand, four hundred thirteen".

Divisors: 1 1879 6989947 13134110413