Base | Representation |
---|---|
bin | 10011000111001101011… |
… | …111010100110101000111 |
3 | 11122120010222110102022120 |
4 | 103013031133110311013 |
5 | 133004332104110333 |
6 | 2443212353301023 |
7 | 163614405416343 |
oct | 23071537246507 |
9 | 4576128412276 |
10 | 1313412566343 |
11 | 467019175869 |
12 | 19266b264773 |
13 | 96b14aba427 |
14 | 477d8a2a623 |
15 | 242716bddb3 |
hex | 131cd7d4d47 |
1313412566343 has 16 divisors (see below), whose sum is σ = 1764496968960. Its totient is φ = 868971877056.
The previous prime is 1313412566339. The next prime is 1313412566377. The reversal of 1313412566343 is 3436652143131.
It is not a de Polignac number, because 1313412566343 - 22 = 1313412566339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313412566295 and 1313412566304.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313412566303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1013796 + ... + 1911702.
It is an arithmetic number, because the mean of its divisors is an integer number (110281060560).
Almost surely, 21313412566343 is an apocalyptic number.
1313412566343 is a deficient number, since it is larger than the sum of its proper divisors (451084402617).
1313412566343 is a wasteful number, since it uses less digits than its factorization.
1313412566343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 901606.
The product of its digits is 466560, while the sum is 42.
The spelling of 1313412566343 in words is "one trillion, three hundred thirteen billion, four hundred twelve million, five hundred sixty-six thousand, three hundred forty-three".
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