Base | Representation |
---|---|
bin | 1011111100100000110010… |
… | …0001001011000110111011 |
3 | 1201111121201101010200211112 |
4 | 2333020030201023012323 |
5 | 3210142340310422021 |
6 | 43533435525150535 |
7 | 2523626134034525 |
oct | 277101441130673 |
9 | 51447641120745 |
10 | 13134220014011 |
11 | 4204211875908 |
12 | 15815bb85b44b |
13 | 743722c25555 |
14 | 3359b1b56a15 |
15 | 17b9b7c2ed5b |
hex | bf20c84b1bb |
13134220014011 has 16 divisors (see below), whose sum is σ = 13682133273600. Its totient is φ = 12594365565600.
The previous prime is 13134220013987. The next prime is 13134220014029. The reversal of 13134220014011 is 11041002243131.
13134220014011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13134220014011 - 210 = 13134220012987 is a prime.
It is a super-2 number, since 2×131342200140112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13134220014031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 222305 + ... + 5130093.
It is an arithmetic number, because the mean of its divisors is an integer number (855133329600).
Almost surely, 213134220014011 is an apocalyptic number.
13134220014011 is a deficient number, since it is larger than the sum of its proper divisors (547913259589).
13134220014011 is a wasteful number, since it uses less digits than its factorization.
13134220014011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4908610.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 13134220014011 its reverse (11041002243131), we get a palindrome (24175222257142).
The spelling of 13134220014011 in words is "thirteen trillion, one hundred thirty-four billion, two hundred twenty million, fourteen thousand, eleven".
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