131342212110034 has 4 divisors (see below), whose sum is σ = 197013318165054. Its totient is φ = 65671106055016.

The previous prime is 131342212109989. The next prime is 131342212110041. The reversal of 131342212110034 is 430011212243131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 109077073336009 + 22265138774025 = 10443997^2 + 4718595^2 .

It is a super-3 number, since 3×131342212110034³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131342212109984 and 131342212110011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32835553027507 + ... + 32835553027510.

Almost surely, 2^{131342212110034} is an apocalyptic number.

131342212110034 is a deficient number, since it is larger than the sum of its proper divisors (65671106055020).

131342212110034 is an equidigital number, since it uses as much as digits as its factorization.

131342212110034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65671106055019.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 131342212110034 its reverse (430011212243131), we get a palindrome (561353424353165).

The spelling of 131342212110034 in words is "one hundred thirty-one trillion, three hundred forty-two billion, two hundred twelve million, one hundred ten thousand, thirty-four".