Base | Representation |
---|---|
bin | 1011111100100000110010… |
… | …0101110001100100011001 |
3 | 1201111121201110101222022021 |
4 | 2333020030211301210121 |
5 | 3210142341113020441 |
6 | 43533440011054441 |
7 | 2523626150220061 |
oct | 277101445614431 |
9 | 51447643358267 |
10 | 13134221220121 |
11 | 4204212519aa1 |
12 | 1581600141421 |
13 | 743723258521 |
14 | 3359b1d8c3a1 |
15 | 17b9b7dbc3d1 |
hex | bf20c971919 |
13134221220121 has 8 divisors (see below), whose sum is σ = 14426604544320. Its totient is φ = 11901948748272.
The previous prime is 13134221220119. The next prime is 13134221220137. The reversal of 13134221220121 is 12102212243131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13134221220121 - 21 = 13134221220119 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13134221226121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15027712630 + ... + 15027713503.
It is an arithmetic number, because the mean of its divisors is an integer number (1803325568040).
Almost surely, 213134221220121 is an apocalyptic number.
It is an amenable number.
13134221220121 is a deficient number, since it is larger than the sum of its proper divisors (1292383324199).
13134221220121 is a wasteful number, since it uses less digits than its factorization.
13134221220121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30055426175.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 13134221220121 its reverse (12102212243131), we get a palindrome (25236433463252).
The spelling of 13134221220121 in words is "thirteen trillion, one hundred thirty-four billion, two hundred twenty-one million, two hundred twenty thousand, one hundred twenty-one".
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