131342212320001 has 4 divisors (see below), whose sum is σ = 131343498791872. Its totient is φ = 131340925848132.

The previous prime is 131342212319999. The next prime is 131342212320029. The reversal of 131342212320001 is 100023212243131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131342212320001 - 2¹ = 131342212319999 is a prime.

It is a super-4 number, since 4×131342212320001⁴ (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131342212320061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 643082781 + ... + 643286986.

It is an arithmetic number, because the mean of its divisors is an integer number (32835874697968).

Almost surely, 2^{131342212320001} is an apocalyptic number.

It is an amenable number.

131342212320001 is a deficient number, since it is larger than the sum of its proper divisors (1286471871).

131342212320001 is a wasteful number, since it uses less digits than its factorization.

131342212320001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1286471870.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 131342212320001 its reverse (100023212243131), we get a palindrome (231365424563132).

The spelling of 131342212320001 in words is "one hundred thirty-one trillion, three hundred forty-two billion, two hundred twelve million, three hundred twenty thousand, one".