Base | Representation |
---|---|
bin | 1011111100100000110101… |
… | …0000001011000000000111 |
3 | 1201111121202020022122011010 |
4 | 2333020031100023000013 |
5 | 3210142401434144333 |
6 | 43533441045213303 |
7 | 2523626343540051 |
oct | 277101520130007 |
9 | 51447666278133 |
10 | 13134232334343 |
11 | 42042188202aa |
12 | 1581603a01233 |
13 | 74372564a2a3 |
14 | 3359b36428d1 |
15 | 17b9b8d65563 |
hex | bf20d40b007 |
13134232334343 has 8 divisors (see below), whose sum is σ = 17518482617328. Its totient is φ = 8753068470464.
The previous prime is 13134232334287. The next prime is 13134232334351. The reversal of 13134232334343 is 34343323243131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13134232334343 - 217 = 13134232203271 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13134232332343) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 771594846 + ... + 771611867.
It is an arithmetic number, because the mean of its divisors is an integer number (2189810327166).
Almost surely, 213134232334343 is an apocalyptic number.
13134232334343 is a deficient number, since it is larger than the sum of its proper divisors (4384250282985).
13134232334343 is a wasteful number, since it uses less digits than its factorization.
13134232334343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1543209553.
The product of its digits is 559872, while the sum is 39.
Adding to 13134232334343 its reverse (34343323243131), we get a palindrome (47477555577474).
The spelling of 13134232334343 in words is "thirteen trillion, one hundred thirty-four billion, two hundred thirty-two million, three hundred thirty-four thousand, three hundred forty-three".
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