13134242444441 has 4 divisors (see below), whose sum is σ = 13413694411392. Its totient is φ = 12854790477492.

The previous prime is 13134242444437. The next prime is 13134242444471. The reversal of 13134242444441 is 14444424243131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13134242444441 - 2² = 13134242444437 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13134242444471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139725983405 + ... + 139725983498.

It is an arithmetic number, because the mean of its divisors is an integer number (3353423602848).

Almost surely, 2^{13134242444441} is an apocalyptic number.

It is an amenable number.

13134242444441 is a deficient number, since it is larger than the sum of its proper divisors (279451966951).

13134242444441 is an equidigital number, since it uses as much as digits as its factorization.

13134242444441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 279451966950.

The product of its digits is 589824, while the sum is 41.

Adding to 13134242444441 its reverse (14444424243131), we get a palindrome (27578666687572).

The spelling of 13134242444441 in words is "thirteen trillion, one hundred thirty-four billion, two hundred forty-two million, four hundred forty-four thousand, four hundred forty-one".