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13134302042 = 26567151021
BaseRepresentation
bin11000011101101110…
…11000101101011010
31020220100111200020012
430032313120231122
5203344340131132
610011145401522
7643323503531
oct141667305532
936810450205
1013134302042
11562aa75584
1226667992a2
131314165674
148c8529318
1551d1300b2
hex30edd8b5a

13134302042 has 4 divisors (see below), whose sum is σ = 19701453066. Its totient is φ = 6567151020.

The previous prime is 13134302039. The next prime is 13134302089. The reversal of 13134302042 is 24020343131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24020343131 = 37649198463.

It can be written as a sum of positive squares in only one way, i.e., 13132930801 + 1371241 = 114599^2 + 1171^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13134301999 and 13134302017.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283575509 + ... + 3283575512.

Almost surely, 213134302042 is an apocalyptic number.

13134302042 is a deficient number, since it is larger than the sum of its proper divisors (6567151024).

13134302042 is an equidigital number, since it uses as much as digits as its factorization.

13134302042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6567151023.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 13134302042 its reverse (24020343131), we get a palindrome (37154645173).

The spelling of 13134302042 in words is "thirteen billion, one hundred thirty-four million, three hundred two thousand, forty-two".

Divisors: 1 2 6567151021 13134302042