Base | Representation |
---|---|
bin | 1011111100100001001000… |
… | …0011001110010101111111 |
3 | 1201111121221211210001021110 |
4 | 2333020102003032111333 |
5 | 3210143033040414424 |
6 | 43533453042333103 |
7 | 2523631341652233 |
oct | 277102203162577 |
9 | 51447854701243 |
10 | 13134312826239 |
11 | 420425a1a8030 |
12 | 158162695a193 |
13 | 743739220527 |
14 | 3359c01d65c3 |
15 | 17b9c0e64c29 |
hex | bf2120ce57f |
13134312826239 has 8 divisors (see below), whose sum is σ = 19104455020032. Its totient is φ = 7960189591640.
The previous prime is 13134312826211. The next prime is 13134312826247. The reversal of 13134312826239 is 93262821343131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13134312826239 - 25 = 13134312826207 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13134312821239) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 199004739759 + ... + 199004739824.
It is an arithmetic number, because the mean of its divisors is an integer number (2388056877504).
Almost surely, 213134312826239 is an apocalyptic number.
13134312826239 is a deficient number, since it is larger than the sum of its proper divisors (5970142193793).
13134312826239 is a wasteful number, since it uses less digits than its factorization.
13134312826239 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 398009479597.
The product of its digits is 1119744, while the sum is 48.
The spelling of 13134312826239 in words is "thirteen trillion, one hundred thirty-four billion, three hundred twelve million, eight hundred twenty-six thousand, two hundred thirty-nine".
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