Base | Representation |
---|---|
bin | 11000011101101111… |
… | …00010101111000001 |
3 | 1020220100120202120001 |
4 | 30032313202233001 |
5 | 203344342434410 |
6 | 10011150320001 |
7 | 643324034332 |
oct | 141667425701 |
9 | 36810522501 |
10 | 13134343105 |
11 | 562aaa3414 |
12 | 26667b9001 |
13 | 131417b270 |
14 | 8c853a289 |
15 | 51d13c33a |
hex | 30ede2bc1 |
13134343105 has 16 divisors (see below), whose sum is σ = 16981468560. Its totient is φ = 9694718208.
The previous prime is 13134343093. The next prime is 13134343111. The reversal of 13134343105 is 50134343131.
It can be written as a sum of positive squares in 8 ways, for example, as 927628849 + 12206714256 = 30457^2 + 110484^2 .
It is a cyclic number.
It is not a de Polignac number, because 13134343105 - 217 = 13134212033 is a prime.
It is a super-2 number, since 2×131343431052 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 98191 + ... + 189499.
It is an arithmetic number, because the mean of its divisors is an integer number (1061341785).
Almost surely, 213134343105 is an apocalyptic number.
It is an amenable number.
13134343105 is a deficient number, since it is larger than the sum of its proper divisors (3847125455).
13134343105 is a wasteful number, since it uses less digits than its factorization.
13134343105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93540.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 13134343105 its reverse (50134343131), we get a palindrome (63268686236).
The spelling of 13134343105 in words is "thirteen billion, one hundred thirty-four million, three hundred forty-three thousand, one hundred five".
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