Base | Representation |
---|---|
bin | 1011111100100001011101… |
… | …0100000111110100010000 |
3 | 1201111122011222221221202202 |
4 | 2333020113110013310100 |
5 | 3210143223143021112 |
6 | 43533505515302332 |
7 | 2523633463431542 |
oct | 277102724076420 |
9 | 51448158857682 |
10 | 13134401142032 |
11 | 42042a5038a95 |
12 | 158165044a9a8 |
13 | 7437516029b1 |
14 | 3359cbc25692 |
15 | 17b9c8aac6c2 |
hex | bf217507d10 |
13134401142032 has 40 divisors (see below), whose sum is σ = 26329801213440. Its totient is φ = 6339689175680.
The previous prime is 13134401142019. The next prime is 13134401142089. The reversal of 13134401142032 is 23024110443131.
It is a Harshad number since it is a multiple of its sum of digits (29).
It is a junction number, because it is equal to n+sod(n) for n = 13134401141986 and 13134401142004.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 434513 + ... + 5143695.
It is an arithmetic number, because the mean of its divisors is an integer number (658245030336).
Almost surely, 213134401142032 is an apocalyptic number.
It is an amenable number.
13134401142032 is an abundant number, since it is smaller than the sum of its proper divisors (13195400071408).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13134401142032 is a wasteful number, since it uses less digits than its factorization.
13134401142032 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4715231 (or 4715225 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 13134401142032 its reverse (23024110443131), we get a palindrome (36158511585163).
The spelling of 13134401142032 in words is "thirteen trillion, one hundred thirty-four billion, four hundred one million, one hundred forty-two thousand, thirty-two".
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