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131344401141 = 32127114911987
BaseRepresentation
bin111101001010010111…
…1001000001011110101
3110120000121122220021200
41322110233020023311
54122443131314031
6140201102203113
712326556663132
oct1722457101365
9416017586250
10131344401141
1150780543658
1221556b83499
13c502587675
1464ddc67589
15363adc48e6
hex1e94bc82f5

131344401141 has 12 divisors (see below), whose sum is σ = 191213548032. Its totient is φ = 86873461416.

The previous prime is 131344401107. The next prime is 131344401163. The reversal of 131344401141 is 141104443131.

It is not a de Polignac number, because 131344401141 - 214 = 131344384757 is a prime.

It is a super-2 number, since 2×1313444011412 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131344401941) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 57454851 + ... + 57457136.

It is an arithmetic number, because the mean of its divisors is an integer number (15934462336).

Almost surely, 2131344401141 is an apocalyptic number.

It is an amenable number.

131344401141 is a deficient number, since it is larger than the sum of its proper divisors (59869146891).

131344401141 is a wasteful number, since it uses less digits than its factorization.

131344401141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114912120 (or 114912117 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 131344401141 its reverse (141104443131), we get a palindrome (272448844272).

The spelling of 131344401141 in words is "one hundred thirty-one billion, three hundred forty-four million, four hundred one thousand, one hundred forty-one".

Divisors: 1 3 9 127 381 1143 114911987 344735961 1034207883 14593822349 43781467047 131344401141