131344422541151 has 4 divisors (see below), whose sum is σ = 131367640581552. Its totient is φ = 131321204500752.

The previous prime is 131344422541091. The next prime is 131344422541181. The reversal of 131344422541151 is 151145224443131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131344422541151 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131344422541099 and 131344422541108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131344422541181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11609011715 + ... + 11609023028.

It is an arithmetic number, because the mean of its divisors is an integer number (32841910145388).

Almost surely, 2^{131344422541151} is an apocalyptic number.

131344422541151 is a deficient number, since it is larger than the sum of its proper divisors (23218040401).

131344422541151 is an equidigital number, since it uses as much as digits as its factorization.

131344422541151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23218040400.

The product of its digits is 230400, while the sum is 41.

Adding to 131344422541151 its reverse (151145224443131), we get a palindrome (282489646984282).

The spelling of 131344422541151 in words is "one hundred thirty-one trillion, three hundred forty-four billion, four hundred twenty-two million, five hundred forty-one thousand, one hundred fifty-one".